4x^2+55x+50=0

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Solution for 4x^2+55x+50=0 equation:



4x^2+55x+50=0
a = 4; b = 55; c = +50;
Δ = b2-4ac
Δ = 552-4·4·50
Δ = 2225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2225}=\sqrt{25*89}=\sqrt{25}*\sqrt{89}=5\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-5\sqrt{89}}{2*4}=\frac{-55-5\sqrt{89}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+5\sqrt{89}}{2*4}=\frac{-55+5\sqrt{89}}{8} $

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